Sed replace last occurrence I'm trying something like Try the following: sed '/desc/ s/{\([^}]*\)}/[\1]/g' filename The search and replace in the above command will only be done for lines that match the regex /desc/, however I don't think this is actually necessary because sed processes text a line at a time, so even without this you wouldn't be replacing braces on the 'entry' block. Modified 5 years, I'm having a problem finding out how to replace the last ', ' in a string with ' and ': Having this string: test1, test2, test3. Then, we use the sed s command to “substitute” the first occurrence of Mavs with Lakers. Adding text to a file 2 lines before the last pattern match. s - The substitute command, probably the most used command in sed. The code below replaces every 3rd occurrence of the word specified in the sed command. For lines that only have one occurrence of “West”, no replacement is made. Here is the rev way to match the third from last occurrence of the letter 's' – still forward matching, yet utilizing rev to match from the last character. Commented Nov 18, 2020 at 9:11. sed -i '4 s/bye/adieu' file Also, if the occurrence is in the last line. *\)-is greedy: it will match everything up to the last -. How do I replace the last character and insert a character to the beginning of a string? 8. cat <<EOF | Thing Wod Stuff1 Wod Stuff2 EOF sed -n ' # omit all the initial lines until # Wod is encountered /^Wod$/!{ p d } : a { # Hold the line H # read next line n # if its the Wod line /Wod/{ # that means that the Wod in hold space # is not the last one # print the hold space as it is and remove it x s/^\n// p s/. sed-remove all but last occurrence of a character from a line. 💡 Pro Tip: To follow along all the examples smoothly, use sed. js , a browser-based sed simulator. The sed substitute command has the form s/old/new/ where old is a regular expression. hek2mgl. finding first and last occurrence of a string using awk or sed. 8. Change the last letter of a string. What I came up with is. Replace last occurrence of space with sed. txt > out_file. Specifically I want the <filename> to come last. Follow edited Nov 12, 2017 at 17:11. sed command to add text for only last line in unix. To do this, replace matching-any-char . csv Also tried but the greedy regex is still the problem. I need to replace the last occurrence of space in an input file, using sed. txt and replaces it with /. Stack Exchange Network. The following example shows how to use this syntax in practice. And only if that it is the last occurrence appearing before an e appearing completely by itself. This is the closest I can figure, not sure how to match across any number of lines not containing more matches of }$: sed -i 's/}$\n. Follow edited Feb 3, 2020 at 10:47. How do I replace only the last occurrence of "-" in a string with a space using sed? For example: echo $MASTER_DISK_RELEASE swp-RedHat-Linux-OS-5. / / / - Delimiter character. Then, we use a loop to obtain the rest of the file. Using sed to replace last occurrence. txt You have over complicated your reg-ex. Although there is no direct sed option for this operation, here is a practical approach: replace the last occurrence of the string with: $ sed -E 's/(. All you need is that the . Running the command without round brackets works fine (for what it's supposed to do - replace the space and the chain of numbers If you are using GNU sed, try:. input Here, I used ## as a placeholder, replace only the last | of the line with it, replace all the other |, and then put back the last one. Lastly, we use tac to re-reverse the file. Replace the "pattern" on second-to-last line of a file. I‘ll also dive deeper into sed Let‘s first see how to isolate and replace the last occurrence within an input string using sed. you can have other than "_" between the numbers, you may which to change only one occurrence in a different way, it may even not be reasonable to manually say how many elements you have. 5. You probably meant "how to remove the last character of the I have a folder full of tar archives, each one of them containing multiple files. In your case, it's added by echo which always adds one unless you use the -n option (with some implementations), or add a \c (with others, the standard ones, not the case of yours which seems to supports that non-standard -e). Ask Question Asked 5 years, 7 months ago. Gaps in the Naive Approach. It supports the ? non-greedy modifier: $ perl -pe 's/. * matches everything and deletes all of the text found there. sed -e '0,/claudio/ s/claudio/claudia/' nomi sed does not start checking for the regex that ends a range until after the line that starts that range. echo "a declaration of sovereignty need no witness" | rev | sed I need to replace the last space per line with a "@", e. This might work for you (GNU sed): Use greed to swallow To replace it in a multiline string shell variable, with GNU sed, you can use the -z option which treats the input as NUL delimited instead of newline delimited: var=$(printf %s "$var" | sed -z '') Although there is no direct sed option for this operation, here is a practical approach: replace the last occurrence of the string with: $ sed -E 's/(. From man sed (POSIX manpage, emphasis mine):. You could even say c17l to change the next 17 Is there an easy way in javascript to replace the last occurrence of an '_' (underscore) in a given string? javascript; Share. tex This is the same as the first answer, except it matches the last / and all the characters after it, and then replaces them with a / (in effect, leaving the final / in the input line alone). I'm using sed to switch integers (one or more digits) to the other side of the ':' colon. txt and replaces it with nothing, this finds /one. 9. Assume I have temp. Suppose that we have the following string that represents an employee ID: A003EmployeeGreg; And suppose that we would like to replace the last “e” in It is changing from 00001148 to 00001147 for both the occurrence of 00001148. I get the aforementioned output using the tar command, looking for This command should do the trick (providing you are looking at myfile. How can I replace the last space per line with "@"? Is there a way to replace the last occurrence of a pattern using shell substitions (IOW, without rolling out sed, awk, perl, etc. Share Pipe that into sed which adds s/. 2 at RedHat (you can test it here if you like) $ sed -n '/class Foo2 {/,/^}$/{s/^}$/Insert here\n\0/};p' file I assumed that the file could contain more classes , and i try to insert my text (insert here) before the end of class Foo2 in the middle of file. *\)ABC$/\1DEF/g' The problem here is that the regex is too greedy, but i cannot make is stop. *$/@/g' file. Also, don't confuse the two circumflexes ^, as they have different meanings: first one matches beginning of string, second one means Sed - Replace last occurrence of match for each line. sed -i '$ s/hello/salut' file But, how can I find and replace the last bye without indicating the line number? Using sed, how can I replace the Nth to last occurrence of a character on each line of a given file? In this case I want to replace the 3rd to last ; with ,. *\)YY/\1XX/' YYthisYYisXXjust XXa XXtest The sed code annotated: s/XX/YY/g; # change all XX to YY s/\(. Using sed to replace the last occurrence of character. Thanks for your help. How to Thiscommand will replace the first occurrence of search_pattern with replacement_text. Use sed to change first occurrence after match. The P command prints upto and including the first newline in the pattern space. sh rm /boot/setup. $ sed -f replace-nth-occurrence. 2. I only want the first one occurrence to be replaced. 157k 28 28 (NF-1)}: awk has out of the box NF variable which has number of fields for any line, since we don't text after last occurrence of -and field separator is -, Using sed to replace last occurrence. Replacing the Last Match in a String The later part of your question (about replacing the last occurrence) is much different imho and should be asked as a separate question - and perhaps better asked on the Unix & Linux site. Let’s say that we have a file named teams. A bit changed rc. Replace i=3 with i=n to make this work for any n. SED incorrectly replaces only the first instance of a pattern on a line. *\)this/\1that/' Having a file containing repeated commented lines like: I want to add a line only after the last occurrence resulting in. gensub allows to reuse the first matched pattern by a special adjustment \1. It should be used in a linux bash script. For n=2, the command is: This way, sed replaces a dash followed by anything-but-dash till the end of the line. Hot Network Questions I'm using centos 7. * to find the last occurence in the file:. 764 1 1 gold badge 9 9 silver badges 24 How to replace last occurrence of characters in a string using javascript. Then pass it to sed and tell it to replace the nth occurrence of your string. echo "fOO:paSS,tesT2:fail @Taavi the s/,/\n/2 command replaces the second , with a newline. you assumed more than I said in the question. Sed regex isn't being as greedy as it ought. So, where the first answer finds one. Faucibus turpis a ac. sed: replace only the first occurrence of wildcard. Then it will change (c) everything up to the end (e) of the word with the string two. How to replace only the last occurrence in a file? 0. Commented Dec 12, 2018 at 13:51. Do you know of a better or easier way of using sed or Bash to replace from the last occurrence of a regex match from the end of a line without using rev?. 2. bak), a backup of the original file is created. Viewed 215 times 2 I have a variable that contains a complete path name. *// x } # if Explanation: /dog/ { # find the first occurrence that match the pattern (dog) n # print pattern space and read the next line :a # 'a' label to jump to /dog/! { # if pattern space not contains the searched pattern (second occurrence) N # read next line and add it to pattern space ba # jump back to 'a' label, to repeat this conditional check } # after find the second occurrence What happens here. any END on same line than START is ignored; last END in last input line is supported; if no END after last START, we print from last START till EOF Using sed is there a way to replace all occurrences of a pattern on a line after a character? So, for instance, replacing every space with an underscore after a full stop would transform this: sed search and replace between string and last occurence of character. txt # count number of occurrences GNU sed has the -z option to use the NULL character instead of LF as separator, so for a text file (without NULL) the whole file is processed as one line and you can make use of the greedy . txt fi exit 0 # unwanted code commented out with the above exit I should replace last number with "Active" if it is "0", Or "Inactive" if it is "1". Hot Network Questions Can quantum computers connect to classical computers to produce output? Does Tolkien ever show or speak of orcs being literate? Modifying sed to only change last occurrence. Currently my sed command is changing both two instances of 00001148. The last character in a text file is a newline character, the delimiter of the last line. I've tried with sed but the occurrence of ";0" in the middle of the line gets changed too. After a successful substitution, the flow is transferred to print_only::remove_and_print s Replace last characters in each line. *\)}/\1/' file OK, then I just provided a different solution - I was previously removing the line containing the last }, now I'm just removing the last } char (AND optionally a preceding newline if present as I'm guessing that's what you'd What if we reverse the string, change the FIRST occurrence in reversed string by sed, then reverse the result back to normal order: #!/bin/bash str="aaa bbb ccc bbb aaa" echo "${str}" | rev | sed 's/bbb/zzz/' | rev It works fine, if we need to replace just one symbol. 5. and the idea is to remove all part after the last : occurrence and get : >scaffold_1:52559-5269(+):mus_musculus AAAGAAAATAATAAA >scaffold_2:27092-2200(+):mus_musculus AAAGAAAATAAT I know the sed command but not for the last occurence. Improve this answer. It can be any character but usually the slash (/) character is used. : Once upon a time there lived a@cat. Modified 5 years, 7 months ago. Patrick. your answer works Using standard sed: $ printf 'XXthisXXisXXjust\nXXa\nXXtest\n' | sed 's/XX/YY/g; s/\(. To do so I'm using this command: But this results in adding my line sed -i "0,\|$old|{s|$old|$new|g}" file should work (although the brackets around the substitute expression are unnecessary, since it is a single expression). txt, but . Replace a matching string from the end of line using sed. sed: search and replace values at position for last line of file. Sed to replace last character on condition. txt 09011111111 This does the job with GNU Sed 4. I tried the command sed '/^[0-9]/ s/. *. Can sed replace new line characters? 2. The forest had many@trees. txt]; then bash /home/pi/setup. The D command deletes upto and including the first newline, then, if the pattern space is not empty repeats all the sed commands from the first but does not replace the pattern space by the next line as the d command would. Replace the nth-from-end occurrence of string in each line. I tried the following solutions: Sed replace at second occurrence; Sed/Awk to delete second occurence of string - platform independent; sed: How to delete second match in a file How to use sed to keep the first two words in the last occurrence of [] Ask Question Asked 9 years, 11 months ago. Of course you can vary e with E, f, F and so on. I loop through them as to get a specific file that starts with baz, is followed by some digits and finally with an underscore _. Replace first occurrence in row. * construction won't consume your delimiter — the colon. I also tried this, to skip the first occurrence of "null": sed -r '0,/null/! s/(\(null)\). $ sed -e 's/,/;/g' -e 's/;/,/1' infile test1,test2;test3 test4,test5 test6,test7;test8;test9;test10 test11,test12;test13;test14 Explanation. – steeldriver I'm tying to replace the last occurrence of a word in a file. EDIT: You should also add a $, if you want to ensure that it is replacing the last occurrence of ABC on the line: sed -e 's/\(. Two alternatives that haven't been brought up until now are to just use other tools for this kind of matching/extraction. *\)-. sed command to replace second occurrence not working to me. This works because \(. txt Team-1: Alex, Bill, Reeta, Ted, Hector Team-2: Sally, David, Alexa, Linda If you change it to sed -E -e 's,foo,bar,g' it works. Wisi eros sed sit nec sed, sed et fringilla vulputate mattis pretium, rutrum vitae vitae euismod erat eu. If you want to replace all on the line AND on the other lines as well it will also work: echo 'dog dog dos\ndog'|sed 's:dog:log:g – Timo. I am trying to conditionally replace the last occurrence of a word in the path. Example: Use sed to Replace Last Line Matching Pattern I am using sed 's/. sed Remove everything above last match found. An editing command with two addresses shall select the inclusive range from the first pattern space that matches the first address through the next Since tac shows the file’s contents with the last line first and the first line last, we use sed to remove the last occurrence of the pattern in the first line we try to substitute the last occurrence of the pattern on that specific line. Improve this question. s/,/;/g replaces all occurrence of , with ; s/;/,/1 replaces the first occurrence of ; with , If you have GNU sed, you can also try this How do I replace the last occurrence of a character in a string I'm trying to use sed to remove the last occurrence of } from a file. I want to substitue matching strings on all but the first occurrence of a line. sed -z 's/\(. 4. Finally, pass the output back through tr to recreate the newlines. This option tells sed to edit files in place. *[=:]//' right now but I get Homer as result (everything after the last = or :) and I would like to get everything after the first, and not the last = or : unix; sed; Share. Basically, it buffers sequences of lines that do not contain a comma. Related Tutorials. Let‘s first see how to isolate and replace the last occurrence within an input string using sed. How to replace only last match in a line with sed? 4. //' and as expected it replaces all the numbers, but I don't know how to make it replace only the second occurrence of each number in the range. Edit: based on question in comments, here is a command that matches on 3rd column and replaces sed -n "/${P1}/,/${P2}/H; /${P1}/h; \${g;p}" The main differences with @Stéphane Chazelas solution, is that here : if multiple STARTs before last END/EOF, we display from last START till last END/EOF. You could rewrite your expression as how to replace the last occurrence of a string exit 0 using awk. The flags can be used to modify substitution behavior – e. Bash get last sentence in line. with negated brackets: [^abc], that match any char except specified. so if regex = #include and replace = blah and the first occurrence grep finds is on line 5 then the I am learning sed, so in this context I am trying to replace 2nd occurrence of word 'line'. sed "s/([ ])[0-9]*$/,/g" However, it does not seem to want to remember the space which it's supposed to replace. sh with the following content: Abc 123 Abc Sdf 2 Abc Abc Utyr Qww I want to replace the last instance of Abc (occurring at the start of a line) with #Abc So finally, the result would be like this: Abc 123 Abc Sdf 2 Abc #Abc Utyr Qww Sed - Replace last occurrence of match for each line. sed to replace in a file, with both old and new strings in files. local if [ -e /boot/disable_rc_setup. hello bye bye bye hello I am able to replace it by indicating the line number. We will utilize backreferences coupled with greedy matches to achieve this. If you want to replace a word in one line, you could also say: $?one<CR>cetwo<ESC> Which will go to the end of the line ($) and find backwards the word one (?one<CR>). sed 's/~/~A/g' infile You need to add 'g' to the end of your sed: sed -e 's/\(. We set the Record Separator RS to null ie ^$, we treat the entire file as one record. The bash script with sed script embedded below:. *: to ^[^:]*:. I tried sed 's/ . I have been through the sed one liners but am still having trouble with my goal. Complex regex sed replacement not working but not throwing errors. We want to replace "something", in this case -), with something unique not found elsewhere in your input, say ~B. txt]; then exit 0 fi if [ -e /boot/setup. Is there a way to do that? While I would prefer a solution with sed, I am open to other command line tools. Ask Question Asked 7 years, 4 months ago. How to replace only last match in a line with sed? Hot Network Questions 80s/90s horror movie where a teenager was trying to get out of pink slime, but can't Modify your regexp ^. Here's a logical solution that uses sed and tr but must be written in a script for it to work. *\)YY/\1XX/; # replace last YY with XX That second substitution will replace the last YY in the modified line with XX since . This means that you could probably simplify Then, with s command replace everything (. When this happens, due to the . How to match the last occurrence of a pattern on and that extra line with the line number is all the way through the subtitle (line 5, line 6line 540). The expected result is: Get a virtual cloud desktop with the Linux distro that you want in less than five minutes with Shells! With over 10 pre-installed distros to choose from, the worry-free installation life is here! Whether you are a digital nomad or just looking for flexibility, Shells can put your Linux machine on the device that you want to use. Additionally, we delay the substitution function’s execution until we have the last line in the pattern space. *)OLD/\1NEW/' input_file As n is usually small you can simply pipe this into the same command n times: That should remove only the last occurrence of a , in any input file - and it will still print those in which a , does not occur. and I want to end out with: test1, test2 and test3. g. sed -n '/SCF Done/p' <filename> | sed '$!d' I would like to replace that command by combining it somehow, but I was yet unable to do so. My target is to replace the OLD to NEW only if COMMAND word appears as the first word in the line. Why does sed not replace all occurrences? 1. sed -e '/ XE/ s/1$/2//' myfile. Sed replace with first characters in line. My exact usage would be: $ echo 'cd /Users/joeuser/bump bonding/initial trials' | sed <<MAGIC HAPPENS> cd /Users/joeuser/bump\ bonding/initial\ trials Replace every occurrence of }. Since the replacement is a string, we need to add an extra \ so the whole replacement became \\1foo\n. As you know by now, sed regexes are greedy and as far as I can tell can't be made non-greedy. Ac feugiat sed elit, pellentesque amet dis, non lorem vero rutrum, vel eu sodales orci a, vestibulum ante consectetur. . But only if that occurrence is at the end of the line. ) -i - By default, sed writes its output to the standard output. First replace all the newlines with a unique character that does not occur anywhere else in your file (e. The cat lived in the@forest. local with unwanted code after the last exit 0: $ cat rc. How to change the first occurrence of a line containing a pattern? 4. Viewed 1k times If the last substitute command made a change to the line, then jump to label a Using sed, tr, and cut to match the described spec of what the output should be, (rather than the inconsistent desired output in the OP):. Weird sed greedy regex behavior. Inside each tar archive there is one such file, for which I want to get the name and output it on a csv file. *\)ABC/\1DEF/g' This tells sed to replace every occurrence of your regex ("globally") instead of only the first occurrence. * is greedy. – Melvyn Sopacua. txt Not a good idea for huge files, but no problem for files like your example. Now let‘s dig into techniques to replace the last match with sed. For words, you need to reverse both, pattern and replacement words. 💡 Pro In this tutorial, we’ll learn a few advanced techniques of using the sed editor to replace the n th occurrence of a string. 0-03 but I want to get the following output ( replacing the last hyphen [“-“] with a space ) swp-RedHat-Linux-OS A fun way to do this, is to use rev to reverse the characters of each line and write your sed replacement backwards. *\n. *)OLD/\1NEW/' input_file In this comprehensive 3k+ word guide, I‘ll cover a variety of practical techniques to replace the last occurrence of a pattern in a file using sed. . The following sed command replaces the OLD string with the NEW string. How to remove string between two characters and before the first occurrence using sed. 181. *?NUM://' data. Hot Network Questions A general approach for "replace the nth-to-last one of something" with pure (GNU) sed. 0. Using sed to replace the second instance of an entire Slurp the file into memory and substitute the last occurrence of the desired string using greed. *\)(\* cds_ams_schematic \*)/\1/' yourfile. *[/]//' in_file. 1. I have to search for |00001148| of last occurrence and replace with another number. txt > output. So whether somethingelse or somethingnew are part of the match doesn't matter, we're matching all chars until we find the last / char in the line. You can use perl as a drop-in replacement for sed with the -pe parameters. 12. You need to do this in order to create a single string for sed. sed teams. * in regex matches on the "greediest match" principle, that is it will match as far to the right as it can. Note that including the g (global) Example: Use sed to Replace Last Occurrence of Character in String. Code: # replace new lines with '^' character to get everything onto a single line tr '\n' '^' < input. Just make sure you have no ## in your input. I want to keep the first two words in the last pair []: eight nine los angeles yes no Sed : replace words only with first occurrence of string in the line not till last match. If an extension is supplied (ex -i. Other attempt, if you really require to replace only on the third to last line (no replacement if there is no match, no replacing on the next-to-last or last line): We can pipe into the following sed expression, targeting the exact occurrence: sed -e 's/foo/bar/3' The third occurrence is replaced: echo "foo foo foo foo foo" | sed -e 's/foo/bar/3' foo foo bar foo foo You can target a range by adding an inverse expression as end range, and global replace (g). The following tutorials explain how to Unless this is to be part of a pipeline, why sed? Using sed, you'd have to store each occurrence of "AAA" and all subsequent lines until the next occurrence of "AAA" exclusive or the final line of the file, print the block if the end of file has not been reached or perform the substitution if it has. Modified 7 years, 4 months ago. Remove Pattern to first space occurrence with sed. Therefore, I issued following command: (zet:pc:~/text) sed 's/line/LINUX/2' mytextfile this is line 1 this is line 2 this is line 3 this is line 4 this is line 5 But from the output, you can see that 'sed' is not replacing 2nd occurrence of the world 'line'. )? Skip to main content. sed: replacing newline at a given line (or last line) 93. txt containing the names Often you may want to use sed to replace the last occurrence of a specific character or specific pattern in a string. *\n^e$/}{&}/g' file. txt). Share. How to replace only last match in a line with sed? 9. Regex to delete specific spaces with sed. Hot Network Questions The Master Tetrist sed 's/^. Sed - Replace last occurrence of match for each line. Ask Question Asked 7 years, 9 months ago. *csv//' file. In this case, the regex is \(. *\/> criterion in the sed expression, everything is replaced until the very last />. txt You can make sure your replacement is acted by adding the -i option which will modify the file in-place, make sure it's exactly what you are expecting before though. When I hear "get the last XYZ" I think "reverse the file and take the first XYZ": reverse the input, and have sed quit when the first "BEGIN CERT" appears, then re-reverse the data: openssl | tac | sed '/BEGIN CERT/q' | tac Since there's stuff after the last -- sed only replacing last occurrence of match - need to match all. Finding Last occurrence out of multiple occurrences of a regexp using SED Scripting. *) including the last occurrence of the pattern by everything before the pattern (the \1 refers to the part in ()) and the replacement. To make sure that this sequence isn't in your input, we first replace all ~ with ~A:. remove spaces between specific characters, with adjacent occurrences. Check $1 with sed to conditionally replace last occurrence of a word in a path string. */replace to the end number, which results in a 1 line script which is piped into the last sed to run as a script on the file. For example, replace the second through fourth: Notice that the second occurrence of “West” has been replaced in each line of the file. Hot Network Questions Using sed to change the second occurance of bb $ sed 's/bb/new-bb/2' file 1 aa 2 2 3 bb 5 new-bb 2 5 or to change the third occurance of 2 How do I replace the last occurrence of a character in a string using sed? 0. Get first word of match of last line. replacing globally instead of just first match or doing case-insensitive searches. Recall that . In this specific case it is in fact a date, although the question is suppose to be more general than that. For example: "47593:23421" would then be "23421:47593". *thing4[^\n]*\n in gensub matches anything till the last line which contain thing4. Dui wisi massa a ut seddictumst, ultricies sed metus, orci urna amet mauris nibh, leo nec fusce. First, we use the N function to append each line except the last one in the pattern space one at a time. Ask Question Asked 14 years, 3 months ago. grep the last occurrence of a pattern before another pattern. So far I have this: sed -i 's/\(. The scenario is I want to comment out the last occurrence of a word in shell script using sed. ^) using tr. How to replace a string inside an SQL file with sed. 0. How to fix my sed syntax in order to replace OLD with NEW only if COMMAND is the first word in line? (Note: COMMAND word location could be after some spaces from the line beginning. You can use the following basic syntax to do so: echo $my_string | sed 's/\(. An alternative, less memory intensive solution: Using sed to replace last occurrence. ylnoy otfte wgqbwe aejheh wdxs ida zezsxem hty fuqa qtcpr